[M3devel] assignability of fixed and open arrays, was: RE: release engineering 5.8: code generator error for IP address initializers
Tony Hosking
hosking at cs.purdue.edu
Fri Apr 16 17:06:27 CEST 2010
There is no open array in this code. Just a fixed array type and an array constructor. It is perfectly reasonable code.
On 16 Apr 2010, at 08:55, Olaf Wagner wrote:
> Quoting Jay K <jay.krell at cornell.edu>:
>
>> (back to the topic :) )
>>
>> somewhat reduced case:
>>
>> MODULE Main;
>>
>> TYPE T1 = ARRAY [0..0] OF INTEGER;
>>
>> CONST const: T1 = ARRAY OF INTEGER{2};
>> BEGIN
>> END Main.
>>
>> The problem is two global integers are overlapping.
>> The open array size and its first element.
>>
>> Are these syntaxes legal?
>> This apparent mixing of open and fixed arrays?
>
> You mean it would work for
>
> CONST const: T1 = ARRAY [0..0] OF INTEGER{2};
>
> The type of const is no open array, but the fixed array A1.
> So the question would be: is an open array (of the correct size)
> assignable to a fixed array type?
>
> An expression e is assignable to a variable v if:
>
> * the type of e is assignable to the type of v, and
> * the value of e is a member of the type of v, is not a local procedure,
> and if it is an array, then it has the same shape as v.
>
> though this is not a variable assignment, but a constant definition.
> Nonetheless, if that's assumed to be equivalent, then it would depend
> on the definition of shape: does it include the length field or not?
>
> I'd tend to think it does not (since that's just a representation the
> compiler (writer) chose), but only the number of dimensions and elements
> should count.
>
> But this is certainly subtle and others may see it differently.
>
> Olaf
> --
> Olaf Wagner -- elego Software Solutions GmbH
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